52 lines
1.7 KiB
Python
52 lines
1.7 KiB
Python
'''样例数据
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red:9188561;ied:10745056;accX:209;accY:-438;accZ:-169
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red:9185136;ied:10744763;accX:209;accY:-438;accZ:-171
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red:9182875;ied:10744312;accX:209;accY:-438;accZ:-171
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red:9181788;ied:10744212;accX:209;accY:-441;accZ:-163
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red:9180729;ied:10744341;accX:209;accY:-441;accZ:-163
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red:9179405;ied:10742269;accX:212;accY:-440;accZ:-172
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red:9178563;ied:10741796;accX:212;accY:-440;accZ:-172
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red:9178557;ied:10742843;accX:209;accY:-440;accZ:-166
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red:9178185;ied:10742777;accX:209;accY:-440;accZ:-166
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red:9177053;ied:10737766;accX:210;accY:-440;accZ:-166
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'''
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import numpy as np
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import pandas as pd
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from pathlib import Path
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def parse_dat_line(line: str) -> dict:
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"""
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解析一行 .dat 文件内容，返回一个字典
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例如输入:
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red:9188561;ied:10745056;accX:209;accY:-438;accZ:-169
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"""
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data = {}
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parts = line.strip().split(';')
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for part in parts:
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if len(part.strip()) == 0:
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continue
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key, value = part.split(':', 1)
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data[key.strip()] = int(value.strip())
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return data
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def parse_dat_file(file_path) -> pd.DataFrame:
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"""
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读取整个 .dat 文件并返回 pandas DataFrame
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:param file_path:
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:return:
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"""
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records = []
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with open(file_path, 'r', encoding='utf-8') as f:
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for line in f:
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parsed_line = parse_dat_line(line)
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records.append(parsed_line)
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df = pd.DataFrame(records)
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return df
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if __name__ == '__main__':
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# file_path = './data/spo2hr[42-A3-C5-2F-F7-32]2025.11.17_17.01.13.dat'
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file_path = './data/spo2hr[42-A3-C5-2F-F7-32]2025.11.17_17.12.15.dat'
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file_path = Path(file_path)
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df = parse_dat_file(file_path)
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df.to_csv(file_path.with_suffix('.csv'), index=False) |